1.查壳
PE32 无壳
2.IDA静态分析
(1)main
// attributes: thunk
int __cdecl main(int argc, const char **argv, const char **envp)
{
return main_0(argc, argv, envp);
}
main_0
int __cdecl main_0(int argc, const char **argv, const char **envp)
{
int v3; // eax
const char *v4; // eax
size_t v5; // eax
char v7; // [esp+0h] [ebp-188h]
char v8; // [esp+0h] [ebp-188h]
signed int j; // [esp+DCh] [ebp-ACh]
int i; // [esp+E8h] [ebp-A0h]
signed int v11; // [esp+E8h] [ebp-A0h]
char Destination[108]; // [esp+F4h] [ebp-94h] BYREF
char Str[28]; // [esp+160h] [ebp-28h] BYREF
char v14[8]; // [esp+17Ch] [ebp-Ch] BYREF
for ( i = 0; i < 100; ++i )
{
if ( (unsigned int)i >= 0x64 )
j____report_rangecheckfailure();
Destination[i] = 0;
}
sub_41132F("please enter the flag:", v7);
sub_411375("%20s", (char)Str);
v3 = j_strlen(Str);
v4 = (const char *)sub_4110BE((int)Str, v3, (int)v14);
strncpy(Destination, v4, 0x28u);
v11 = j_strlen(Destination);
for ( j = 0; j < v11; ++j )
Destination[j] += j;
v5 = j_strlen(Destination);
if ( !strncmp(Destination, Str2, v5) )
sub_41132F("rigth flag!\n", v8);
else
sub_41132F("wrong flag!\n", v8);
return 0;
}
程序逻辑分析:
(1)用户输入为Str,在第24行执行sub_4110BE对其进行处理。
(2)将用户输入处理后的返回值v4复制给数组Destination。
(3)对数组Destination进行元素和下标的循环加和。